Question

In the given ABC, E is a point on AD. If AEB, ADB and ACD are equal to 180° – k1, 180° – k2 and 180° – k3 respectively, then k1 : k2 : k3 equals

Answer 1

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k1 : k2 : k3

4∝ + 180 - k3 = 180

4∝ = k3

In AEB

∝ + 180 - k1 + ∝ = 180

2∝ = k1

k1 = 2∝ = k3/2

In the triangle ABC

∝ + k2 + 180 - k3 = 180

∝ = k3 - k2

k2 = k3 -∝

= 4∝ -∝

= 3∝

k1 = 2∝

k2 = 3∝

k3 = 4∝

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