Question

In the given adjoining figure ab is a diameter of a circle with centre o and cp is a tangent to a circle at point c. if ap=20cm, cp=10cm, find the radius of the circle

Answer 1

$here \: it \: is \: mate$

GIVEN :::::::

AP = 20

CP = 10

AO = OB = OC = RADIUS OF THE CIRCLE

TO FIND :::::::

RADIUS OF THE CIRCLE

FORMULA USED :::::

PYTHAGORAS THEOREM

HOW TO FIND :::::

WE KNOW CPO IS A RIGHT TRIANGLE RIGHT ANGLED AT C.

SO BY APPLYING PYTHAGORAS THEOREM::::

PO² = OC² + CP²

NOW,

AP = 20

AP = AO + PO

WE KNOW, AO = R (RADIUS)

THEN, PO = AP - AO = 20 -R

THEREFORE,

(20 - R)² = CP² + CO²

400 - 40R + R² = 100 + R²

400 - 40R = 100

40R = 300

R = 300/40

R = 7.5 cm

HOPE IT HELPS U.....PLEASE MARKS AS BRAINLIEST.....

Answer 2

Answer is in the attachment.