Question

in the given angle b=90 °ab=6cm,bc=8cm and ac=10cm then the value of sin(90°-theta)​

Answer 1

Answer:

sin(90°-theta)=4/10

Step-by-step explanation:

sin(90°-theta)= cos (theta)

cos(theta)= adjacent side/hypotenuse

=8/10

=4/5

Answer 2

Answer:

8/10

Step-by-step explanation:

sin(90-theta)=cos theta

so cos = A/H

BC/AC

8/10

OR

4/5