Question

In the given AP 10, -5, -20.......Find the 14th term.​

Answer 1

Answer:

Heya mate your answer

Step-by-step explanation:

Given, 14th term = 2 ( 8th term )

=> a+13d = 2 (a+7d)

=> a+13d = 2a+14d

=> 2a–a = –14d+13d

=> a = –d

And 6th term = –8

=> a+5d = –8

Substituting a = –d in this equation

=> a+ (–5a) = –8

=> –4a = –8

=> a = 8 / 4

=> a = 2

So, d = –2

Sum of 20 terms = n/2 [ 2a + ( n–1) d ]

=> 20/2 [ 2(2) + (20–1) –2 ]

=> 10 [ 4 + 19 (–2) ]

=> 10 [ 4 – 38 ]

=> 10 × –34

=> –340

Answer 2

Answer:

-185

Step-by-step explanation:

Difference is -15 each time

a = 10

d = -15

the 14th term is 10 + 13(-15)

= 10 - 195

=-185

therefore,the 14th term is -185

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