Question

In the given AP = 4cm, BQ = 6cm and AC = 9cm. find the semi perimeter of ΔABC.​

Answer 1

Semi perimeter of a triangle is given by :

$\frac{a + b + c}{2}$

Here let a be 4cm, b be 6cm and c be 9cm.

Therefore,

$\frac{4 + 6 + 9}{2}$

$= \frac{10 + 9}{2}$

$= \frac{19}{2}$

$= 9.5cm$

Hence semi perimeter = 9.5 cm

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