Question

In the given arrangement, the normal force applied as by block on the ground is
(1)mg
(3) mg + Fcose
(2) mg – Fcose
(4) Fcoso
​

Answer 1

Answer:

Fcos&

because F force has 2 components acc. to physics that

• F cos $ along theta that equal to normal
• and another F sin$ that moves the box ahead

that F force in physics cannot calculated that way so we have to take components