In the given arrangement, the normal force applied by block on the ground is
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Answered by
17
Answer:
Fcos(theta)
Explanation:
Normal force applied is the cos component of the force F.
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Answered by
37
Answer:
Explanation:
We are given that force applied on the block=F
Mass of block=m
We have to find the normal force applied by block on the ground
When we resolve F then
Vertical component=
Horizontal component=
Let N be the normal applied by the block on the ground
Then , N and are applied in the same direction
Hence, the normal applied on the block=
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