Question

In the given arrangement, the normal force applied by block on the ground is
(1) mg
(3) mg + Fcose
(2) mg - Fcose
(4) Fcose​

Answer 1

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✍ (2)mg - Fcos e

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EXPLANATION —

Force are acting in angle e(theta) with vertical component

Therefore, vertical component of force is Fcos e

Since Normal force is mg before acting any force

Acting opposite

Therefore the force will be subtracted from MG

mg - Fcos e

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