In the given arrangement,the normal force applied by block on the ground is
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Answer:
In the given arrangement, The normal force applied by block on the ground is :

A
mg
B
mg - fcosθθ
C
mg+Fcosθmg+Fcosθ
D
FcosθFcosθ
Solution

N+Fcosθ=mgN+Fcosθ=mg
N=mg−FcosθN=mg−Fcosθ
Hence,
option (B)(B) is correct answer.
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