CBSE BOARD XII, asked by rithuljthomas9885, 11 months ago

In the given arrangement,the normal force applied by block on the ground is

Answers

Answered by sankhadeep71
0

Answer:

In the given arrangement, The normal force applied by block on the ground is :

A

mg

B

mg - fcosθθ

C

mg+Fcosθmg+Fcosθ

D

FcosθFcosθ

Solution

N+Fcosθ=mgN+Fcosθ=mg

N=mg−FcosθN=mg−Fcosθ

Hence,

option (B)(B) is correct answer.

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