Question

in the given below figure O is the Centre of the circle DB is diameter find x ​

Answer 1

Answer:

In △ADB

∠DAB=90

o

∠ADB+∠DAB+∠ABD=180

o

30+90+∠ABD=180

o

ABD=60

o

similarly

∠CDB+∠CBD+∠DCB=180

∠CDB+60+90=180

∠CDB=30

o

In △ADBAO=OB

∠OAB=∠OBA=60

o

60+∠BAQ=90

o

∠BAQ=30

o

In △AODOO=OA

∠ODA=∠OAD=30

o

∠OAD+∠OAP=90

o

30+∠DAP=90

∠DAP=60

o

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