In the given below figure, side BC of ∆ABC has been produced to a point D. If ∠A = 3y⁰, ∠B = x⁰, ∠C = 5y⁰ and ∠CBD = 7y⁰. Then, the value of x is *
Answers
Answer:
7y+5y=180(Linear pair)
12y=180
y=180/12
y=15
<ACB=5*15=75
<BAC=3*15=45
let <ABC=X
IN TRIANGLE ABC,
X+75+45=180 (ANGLE SUM PROPERTY)
X+120=180
X=180-120
X=60
Step-by-step explanation:
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Given : In the given below figure, side BC of ∆ABC has been produced to a point D.
∠A = 3y⁰, ∠B = x⁰, ∠C = 5y⁰ and ∠CBD = 7y⁰.
To Find : the value of x
Solution:
7y⁰. and 5y⁰ forms a linear pair
Hence 7y⁰ + 5y⁰ = 180⁰
=> 12y⁰ = 180⁰
=> y = 15
Sum of angle of a triangle is 180⁰
3y⁰ + 5y⁰ + x⁰ = 180⁰
=> 8y⁰ + x⁰ = 180⁰
y = 15
=> 8(15°) + x⁰ = 180⁰
=> 120⁰ + x⁰ = 180⁰
=> x⁰ = 60⁰
=> x = 60
Value of x = 60
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