Question

In the given circle, AB is a diameter. Chords
AD = CD, If angle DAB = 70°, find angleABD and
angle ABC.​ please answer

Answer 1

Answer:

Angle ABC 40°

Step-by-step explanation:

let angle B be x

70°+70°+x = 180°

140°+ x = 180°

x = 180°-140°

x = 40°

Answer 2

Answer:

∠ABD =  20° and ∠ABC = 40°

Step-by-step explanation:

Trianlge ADB is based on the diameter so ∠ADB must be equal to 90°.

So, the remaining angle ∠ABD in that triangle becomes 180-90-70 = 20°.

Since both triangles ADB and BCD have equal length of bases and same meeting point, they make inscribed angles. So, ∠ADB = ∠ABD = 20°.

∠ABC = ∠ADB +∠ABD = 20° + 20° = 40°

PS: Plz make mine the brainliest answer, Thankss