In the given circle, AB is a tangent BC is diameter and angle BAO =32⁰.Find the value of angle AOB.
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Step-by-step explanation:
angle AOB = 68⁰
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Here , given cricle AB is tangent
Now,by tangent theorem
Angle ABO = 90 degrees
angle BAO + angle ABO + angle ABO = 180 degrees
- [ sum of measwure of triangle is 180 ]
32 + 90 + angle ABO = 180
122 + angle ABO = 180
angle ABO = 180 - 122
angle ABO = 58 degrees
Now,by tangent theorem
Angle ABO = 90 degrees
angle BAO + angle ABO + angle ABO = 180 degrees
- [ sum of measwure of triangle is 180 ]
32 + 90 + angle ABO = 180
122 + angle ABO = 180
angle ABO = 180 - 122
angle ABO = 58 degrees
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