Question

In the given circle, O is the cen-
tre. LABC = 80°, ZACB –
40°. Find the sum of angles
ZDBC + ZBCD.​

Answer 1

Answer:

Step-by-step explanation:

Angle ABC+ angle ACB+ angle BAC=180

80+40+ angle BAC=180

Angle BAC=60 degree

Angle DBC = 80/2.....bisector

Angle DBC= 40 degree

Angle BCD=40/2

Angle BCD=20 degree

SO THEREFORE,ANGLE BCD+DBC IS EQUAL TO 60

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