Question

In the given circle, the chord PQ is 18 cm in length. AB, the
perpendicular bisector of PQ, intersects it at M. If MB = 3 cm,
find AB.
M
B​

Answer 1

Step-by-step explanation:

Let OA = x = OP = OB

AB = 2x

OM = x - 3

In△OMP

x2=(9)2+(x−3)2

x2=81+x2+9−6x

90=6x

x=15

∴AB=2×15=30cm.

Answer 2

Answer:

AB = 30 cm

Step-by-step explanation:

In ∆OMP

x² = (9)² + (x-3)²

x² = 81 + x² + 9 - 6x

6x = 90

x = 15 cm

Therefore, AB = 2 * 15

30 cm

Hope it helps!!