Question

In the given circle with centre O, RL perpendicular to MQ and angle PMO is25 degree. The difference of the measures of angle QAT and angle LTM is

Answer 1

RL⊥MQ
Hence ∠LOQ=90°
∠LOQ=∠ROQ=90°
OL =OQ,Hence radius of the circle
∠OLQ=∠OQL=90/2=45°
∠MQT=180°-45°=135°
∠QTM=180°-∠MQT-∠QMT=180°-135°-25°=20°
∠QTM=∠LTM=20°
∠TQA=180°-45°-45°=90°
∠QAT=180°-90°-20°
∠QAT=70
∠QAT-∠LTM=70°-20°=50°