Question

In the given circuit, calculate: 2 i) Net resistance of the circuit
ii) Current through 3Ω resistor.

Answer 1

Answer:

THEORY :-

Series combination of resistance ( diagram (a) )

When resistors are arranged in such a way that the ending of the first resistor are connected to the starting point if the second resistor. (please see the diagram ( a) )

In such a case, equivalent resistance of a combination of resistances equals

Req = R1 + R2 + R3...........

The current through any two resistors in series us always same.However, there may be voltage difference across them

parallel combination of resistance

When resistors are arranged in such a way that the are connected across the same point. ( see tha diagram b )

In such a case,

The voltage difference across any two resistor in parallel is always same.

SOLUTIONS

We have ,

2 ohm and 3 ohm resistors are in series .

Req = 2 + 3 = 5.

Now, this will be parallel to 5 ohm resistor. Hence, we get two 5 ohm resistor in parallel.

Req = 5 /2.

(i) Hence, net resistance of the circuit is 5 ohm.

(ii) a . When key K1 will be closed, no current will pass through 5 ohm resistor , hence V = 5 I = 0. Hence, voltage difference will be 0.

(ii) b. When key K2 is closed, no current will pass through 2 and 3 ohm resistors, hence, all current will pass through 5 ohm.Hence, V across 5 ohm = 6 V = V across battery = reading of voltmeter.

(iii) Net current in the circuit = V/Req = 6/2.5 = 2.4

Now, this will distribute into two resistors of 5 ohm and 5 ohm.They both will get 2.4/2 = 1.2 A.

Now, 2 ohm and 3 ohm are in Series, Hence, current flowing through them will be equal and will be 1.2 A.

Explanation:

MARK AS BILLIANT

FOLLOW ME

THANK ME PLEASE

Answer 2

Answer:

Current through 3ω resistor

I

1

=

3

12

=4A

Please mark me as brainliest

Thank you and have a nice day