in the given circuit calculate
(I) effective resistance between A and B
(ii) current through the current
Answers
Answer:
4A
Explanation:
) Finding effective resistance between A and B
(ii) Current through the circuit (I)
(iii) Current through 3ω resistor
(i) Equivalent resistance=
12+8
12×8
+
12
12×8
=
12+8
12×8
+
4+6
4×6
=
20
12×8
+
10
4×6
=
5
12×2
+
5
2×6
=
5
24
+
5
12
=
5
24
ω
5
24
1
+
3
1
+
3
1
=
24
5
+
3
1
+
3
1
=
24
5+8+8
=
24
21
∴R
1
=
21
24
=1.14ω
(ii) Current through the circuit
I=
1.14
12
=10.52A
(iii) Current through 3ω resistor
I
1
=
3
12
=4A
Here,
For first part :
i) In the given circuit , 12 Ω and 8Ω are in parallel combination and also 4 Ω and 6Ω are in parallel combination .
In parallel combination we use :
• 1/R = 1/r1 + 1/r2+ 1/r3.......
After solving this , both becomes in series .
In series combination we use :
• R = r1+r2+r3....
Again solving , all becomes in parallel combination .
Solution refers to the attachment:
Now ,
ii) current through the circuit :
•As we know that :
= V= IR
=> 12 = I (36/35)
=> I = (35×12)/36
=> I = 11.6 A .
