Question

In the given circuit, calculate:
i)the total resistance of the circuit
(ii) the current through the circuit, and
(üi) the potential difference across R, and R,
[2014]​

Answer 1

Answer:

Given, The resistance of conductor R1=4Ω

The resistance of conductor R2 =20Ω

(i) The total resistance of the circuit

R= R1 + R2 (series combination)

R =4+20=24Ω

Now by Ohm's Law,

(ii) The current through the circuit,

V= IR,

I= V/R=6/24=1/4=0.25 Amp.

(iii) The potential difference across the two terminals of the battery = 6V

V1 =Ix R1

= 0.25 x 4 = 1V (Potential difference across the conductor R1)

V2= I x R2

= 0.25 × 20 = 5 v ( Potential differences across the conductor R² .