Question

in the given circuit , calculate total effective resistance in figure A having resistors 1 ohm each and in figure B resistor 3 ohm each​

Answer 1

Answer:this is the answer

Explanation:

Answer 2

Given:

Combination A having resistors 1 ohm each

Combination B resistor 3 ohm each​

To find:

Total effective resistance of the set A and B

Solution:

Combination A:

It has three more subsets inside the circuit where

in two sets three resistors are in parallel combination and then the resultants will be in series

For the parallel connection:

• $\frac{1}{Rp} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3}$
• $\frac{1}{Rp} = \frac{1}{1} + \frac{1}{1} + \frac{1}{1}$
• $\frac{1}{Rp} = 3$

then

Rp = 1/3

as we have two connection like this so Rp' is also 1/3

as now the connection is in series

For the series connection:

Rs = Rp + R4 + Rp'

• Rs = 1/3 + 1 + 1/3
• Rs = 5/3Ω

so,

Rs = 5/3Ω

Combination B:

two resistors are in series

Rs = R1+R2

• Rs = 3+3
• Rs = 6Ω

like this, only the Rs' will be 6Ω only

now the resultants are in the parallel connection

• $\frac{1}{Rp} = \frac{1}{Rs} + \frac{1}{Rs'}$
• $\frac{1}{Rp} = \frac{1}{6} + \frac{1}{6}$
• $\frac{1}{Rp} = \frac{2}{6}$
• $\frac{1}{Rp} = \frac{1}{3}$
• Rp = 3Ω

so,

Rp = 3Ω