. In the given circuit, (Fig. 3.61) calculate :
(a) total resistance of the circuit, and
(b) current shown by the ammeter
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mohittyagi89:
2.5
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As the series combination of resistances 3 Ω and 2Ω is connected in parallel with a resistance of 5 Ω. The net resistance = (5×5)/ (5+5) The net resistance = 25/10 The net resistance = 2.5 Ω Current (I) = V/R I= (2.5/2.5) amp I=1 amp.
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