In the given circuit find
(a) total resistance of the network of resistors
(b) Current through ammeter A
(c) Potential difference across 3ohm and 4ohm resistors
Answers
Answer:
hey mate your pic is not complete.....
Figure given in question is incomplete . The value of emf is 6 V .
Given :
emf of the circuit = 6 V
two serial resistors of 4 ohm and 2 ohm connected in parallel to another two serial resistors of 3 ohm and 3 ohm .
To find :
(a). Total resistance of the circuit .
(b). Current through ammeter A .
(c). Potential difference ( voltage ) across 3 ohm and 4 ohm resistors .
Solution :
(a) . Net resistance = ( 4 + 2 ) || ( 3 + 3 ) ohm
= 6 || 6 ohm
= 3 ohm
(b). Current = 6 V / 3 ohm
= 2 A
(c). 1 A current will be flow in both parallel parts .
potential difference across 3 ohm = [ 3 / ( 3 + 3 ) ] * 1
= 0.5 V
potential difference across 4 ohm = [ 4 / ( 4 + 2 ) ] * 1
= 0.67 V
Total resistance of the network of resistors = 3 ohm
Current through ammeter A = 2 Ampere
Potential difference across 3 ohm and 4 ohm resistors are 0.5 V and 0.67 V respectively .