in the given circuit find out the current through the 18 ohm resistor and the net resistor of the circuit.
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total resistance =((6//12)+8)//12)+18=(12//12)+18=24 ohms
thus current through 18 ohm resistor =24/24A=1A
//=> parallel and + => in series
6//12=(6×12)/(6+12)=72/18=4
thus current through 18 ohm resistor =24/24A=1A
//=> parallel and + => in series
6//12=(6×12)/(6+12)=72/18=4
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