Question

in the given circuit,find the power dissipated in 6 ohm ressistance.
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ANS-9 watt (need full process)​

Answer 1

Given:

A circuit has been provided. The voltage source is 20 V

To find:

Power dissipated in the 6 ohm resistor.

Concept:

First find out the equivalent resistance of the circuit. In that equivalent circuit , find out the current . Then the power dissipated can be easily calculated.

Power is the amount of energy dissipated by the resistance per unit time.

Calculation:

See the diagram for simplified circuit.

The 5 ohm, 4 ohm and 6 ohm are in series.

So net current will be :

I = \dfrac{V}{(5 + 4 + 6)}I=

(5+4+6)

V

= > I = \dfrac{20}{(15)}=>I=

(15)

20

= > I = \dfrac{4}{3} amp.=>I=

3

4

amp.

Power dissipated in the 6 ohm resistor will be :

P = {(I)}^{2} \times 6P=(I)

2

×6

= > P = {( \dfrac{4}{3} )}^{2} \times 6=>P=(

3

4

)

2

×6

= > P = \dfrac{16}{9} \times 6=>P=

9

16

×6

= > P = 10.66 \: watt=>P=10.66watt

So final answer :

\huge{ \green{ \sf{ \bold{ P = 10.66 \: watt}}}}P=10.66watt