Question

in the given circuit
Rc= 3 kohm, VCE = 6 V and VBE= 0.7 V.
If B = 50, the base resistor Rb will be
(1) 7.5 x 104 32
(3) 4.5 * 1052
(2) 5 x 1042
(4) 1.125 105 22​

Answer 1

Answer:

Resistance of base resistor is given as

$R_b = 1.75 \times 10^4 ohm$

Explanation:

As we know that voltage gain in common emitter transistor is given as

$\frac{v_{CE}}{v_{BE}} = \frac{i_c R_c}{i_b R_b}$

also we know that current gain in this transistor is given as

$\beta = \frac{i_c}{i_b}$

$\beta = 50$

$\frac{v_{CE}}{v_{BE}} = \frac{3000}{R_b} \times 50$

$\frac{6}{0.7} = \frac{150000}{R_b}$

$R_b = 1.75 \times 10^4 ohm$

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Topic : Transistor

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Answer 2

The base resistance is $1.75\times10^{4}\ \Omega$

(1) is correct option.

Explanation:

Given that,

Capacitor resistance = 3 kohm

Voltage $V_{CE}=6\ V$

$V_{BE}=0.7\ V$

Current gain $\beta =50$

We need to calculate the base resistance

Using formula of voltage gain in common emitter

$\dfrac{V_{CE}}{V_{BE}}=\dfrac{i_{C}}{i_{B}}\times\dfrac{R_{C}}{R_{B}}$

We know that,

The current gain is

$\beta=\dfrac{i_{C}}{i_{B}}$

Put the value into the formula

$\dfrac{6}{0.7}=\dfrac{3000}{R_{B}}\times50$

$R_{B}=\dfrac{3000\times0.7}{6}\times50$

$R_{B}=17500\ \Omega$

$R_{B}=1.75\times10^{4}\ \Omega$

Hence, The base resistance is $1.75\times10^{4}\ \Omega$

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Topic : current gain

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