Question

In the given circuit , the current in the arm BD is

Answer 1

Pls provide the circuit.... Incomplete question.

Answer 2

Answer:

1,4&2,3 in parallel separately.

R

eq

=(

4+1

1×4

)+(

2+3

2×3

)

=

5

4

+

5

6

=

5

10

R

eq

=2Ω

i=

R

V

=

2

20

=10A

i=10A

i

1

=

5

4

×10=8A

i

2

=

5

3

×10=6A

i

BD

=i

1

−i

2

=8−6=2A

C

BD

=2A

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