In the given circuit, the potential difference across
3 uF capacitor will be :
20V
3uF+
5uF
4V
th
(1) 16 V
(2) 10 V
(4) 4 V
(3) 6 V
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The potential difference across 3 uF capacitor will be 10 v
Explanation:
- Both capacitor and battery are in series so
V(eq) = 20 - 4 = 16 v
C (e q) = 3×5 / 5+3 = 15 / 8
q = C( eq) ×V( eq) = 15/8 × 16 = 30
V3 = q /c = 30 / 3 = 10 v
Thus the potential difference across 3 uF capacitor will be 10 v
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