Question

In the given circuit the potential difference across 3mf capacitor is

Answer 1

Answer:

$C1 = 2\mu\,{F}$

$C2 = 4\mu\,{F}$]

$Ceq = \dfrac{2\times 4}{2 + 4} =\dfrac{4}{3}\mu\,{F}$]

$]\text{total charge Qt} = \dfrac{4}{3}\times 1200 = 1600\mu\,{Coulombs}$]

$]\text{ for series circuit Qt = Q1 = Q2}$

$]\text{Voltage across C1} = \dfrac{Qt}{C1}= \dfrac{1600}{2}= 800 V$]

Answer 2

Answer:

Here is your answer ll

Hope it helps you