Question

In the given circuit, the potential difference between A and B is 18 V and charge on 2uf capacitor is 24uC
The value of C
(1)1uF
(2) 2 UF
(3) 3uF
(4) 4uF​

Answer 1

Explanation:

........................

Answer 2

Answer:

The value of "C" is 1μf.

Explanation:

From the question we have,

The total potential difference of the circuit is =18 volt

The charge on the 2μf capacitor is =24μC

We will use the following formula to solve the question,

$Q=CV$     (1)

Where,

Q= charge on the capacitor

C=capacitance of the capacitor

V=voltage across the capacitor

The voltage across the 2μf capacitor will be,

$24\mu C=2\mu F \times V$

$V=12 volts$     (2)

The voltage across the 6μf capacitor will be,

$V'=18-12=6V$

And the charge on the 6μf capacitor will be,

$Q'=6\muF \times 6V=36\mu C$

So, the left charge on the capacitor "C" is,

$Q''=36\mu C-24\mu C=12\mu C$    (3)

The value of C using equation (1) is,

$12\mu C=12 volts \times C$

The voltage across capacitor "C" is 12 volts as the 2μf capacitor and "C" are connected in parallel combination.

$C=\frac{12}{12} =1\mu F$

Hence, the value of "C" is 1μf.