Physics, asked by arifasherin9991, 1 year ago

in the given circuit voltmeter shows a reading of 4 volt and the power developed across R resistance will be

Answers

Answered by Sujal5563
25

Answer

Dear Student

Net resistance is 2+R

Current in circuit will be

I = V/R  =  10/{2+R}

Now as in series current is same across each resistor

so voltage across resistor R

V=IR

4 =10/(2+R)  *R

8+4R =10R

8=6R

R =1.33 KOhm

P=V*V/R

  =161.33

  =12 mW

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