Question

In the given circuit voltmeter shows a reading of 4V, then the power developed across Rresistance will be


A) 15 mW
B) 14 mW
C) 12 mW
D) 10 mW

Answer 1

Answer:

By assuming zero volt at one end of the battery=

across 2KΩ resistance = ΔV=IR(10−4)=I×(2000)6=I×(2000)I=20006=3mA 

Now power generated through resistance R= (voltage across resistance R)×(current flowing through resistance R)

P = 4×3 m W

P = 12 m W

hope it may help you....have a nice day.