In the given circuit voltmeter shows a reading of 4V, then the power developed across R resistance will be I Is the answer 12mW
Attachments:
Answers
Answered by
4
(3) 12mW is the right option✔
By assuming zero volt at one end of the battery=
across 2KΩ resistance = ΔV=IR
(10−4)=I×(2000)
6=I×(2000)
I= 6/2000
=3mA
Now power generated through resistance R= (voltage across resistance R)×(current flowing through resistance R)
P = 4×3 m W
P = 12 m W
Answered by
2
Answer:
sorry I have no any answer
Similar questions