Question

In the given circuit, what is the total resistance and current supplied by the battery.

Answer 1

First of all we should give name of given resistors
Like R₁ = R₂ = R₃ = 3Ω and R₄ = 2Ω
Now, Let's find equivalent resistance ,
We can see that R₁ , R₂ and R₃ are in parallel
so, equivalent of these three resistors is R'
1/R' = 1/R₁ + 1/R₂ + 1/R₃
1/R' = 1/3Ω + 1/3Ω + 1/3Ω = 3/3Ω = 1/1Ω
R' = 1Ω

Now, R' and R₄ are connected in series so, finally equivalent resistance is Req
e.g., Req = R' + R₄
= 1Ω + 2Ω = 3Ω

Hence, equivalent resistance = 3Ω
Current supplied by the battery = V/Req
Here, V = 6v and Req = 3Ω
∴ current supplied = 6/3 = 2A

Answer 2

In parallel resistors
R₁ = R₂ = R₃ = 3 Ω
Since they are in parallel 
Therefore equvalent resistance is given by 

$1/R_{eq}$  = 1/R₁ +1/R₂ +1/R₃
$1/R_{eq}$ = 1/3 +1/3 +1/3
=(1+1+1)/3
= 1Ω


Now , $1/R_{eq}$  is connected with R (2Ω) in series connection 
∴ Total resistance = 1+2
=3 Ω

Now, By ohms law

V= I × R
6 = I × 3
I = 2 A

Hence current is equal to 2 A


Hope it Helps :-)