Question

In the given circuit with steady current, the potential drop
across the capacitor must be
(a)2V/3
(b)V/3
(c)V/2 (d) V

Answer 1

Explanation:

In steady state, no current will pass through the capacitor

In the lower loop

2V−2iR−iR−V=0

⇒ i=V/3R

For the upper loop, V−V

C

−iR−V=0⇒∣V

C

∣=iR=V/3

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