Question

In the given diagram, AB=AC. O is the centre of the circle. If ABC angle = 80 then find angle BOC​

Answer 1

In ∆ABC,

AB = BC

.°. <ACB = <ABC = 80°

.°. By angle sum property of triangle,

<BAC

= 180 - (<ACB + <ABC)

= 180 - 160

= 20°

.°. <BOC = 20°/2 = 10°

Answer 2

Answer:

in ABC

angle b = angle c (opposite angles of an isocles triangle are equal)

angle a = 180-(angle b + angle c)

angle a=20

angle boc = 20x2

= 40⁰