in the given diagram angle ACD = 105° and angle EAF =45° then, the measure of angle ABC is
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In the figure the sides BC,CA and AB of a △ABC have been produced to D,E and F respectively. If ∠ACD=105
o
and ∠EAF=45
o
, find all the angles of the △ABC
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ANSWER
∠BAC=∠EAF=45
∘
(∵ vertically opposite angles )
∠ACB=180
∘
−∠ACD=180
∘
−105
∘
=75
∘
∠ABC=180
∘
−∠BAC−∠ACB=180
∘
−45
∘
−75
∘
=60
∘
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