Question

in the given diagram o is the centre of the circle. chord ab is parallel to chord cd. ab=64cm and=48cm radius=40 cm. find the distance between the two chords

Answer 1

ANSWER IS 64..............

Answer 2

Answer:

The distance between chords is 56 cm .

Step-by-step explanation:

Given as :

A circle with center o

Two parallel chord are AB and CD

The radius of circle = OC = OA = r = 40 cm

Let The distance between chords = EF = x cm

According to question

In Δ BOE

OB² = OE² + BE²

Or, r² = OE² + ($\dfrac{AB}{2}$)²

Or, 40² = OE² +( $\dfrac{64}{2}$)²

Or, OE² = 40² - 32²

Or, OE² = 1600 - 1024

Or, OE² = 576

Or, OE = $\sqrt{576}$

i.e OE = 24 cm  

Again

In Δ DOF

OD² = OF² + DF²

Or, r² = OF² + ($\dfrac{CD}{2}$)²

Or, 40² = OF² +( $\dfrac{48}{2}$)²

Or, OF² = 40² - 24²

Or, OF² = 1600 - 576

Or, OF² = 1024 cm

Or, OF = $\sqrt{1024}$

i.e OF = 32 cm  

Since, The distance between chord AB and CD = EF

So, EF = EO + OF

Or, x = 24 cm + 32 cm

Or, x = 56 cm

So, The distance between the chord = x = 56 cm

Hence, The distance between chords is 56 cm . Answer