In the given diagram of a simple pendulum, the time taken by the bob to move from X to Z is 't1' and from Zto O is 't2'.The time period of this simple pendulum is -
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70
I think the answer is 4(t1+ t2), as t(XOYOX) is time period. Pendulum requires same time to cover XO to OY and XZ + XO = XO
Answered by
27
the time of the simple pendulum is 4(t1+t2)
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