Question

In the given diagram, PO and RS are common
tangents to the two cindes with centres and D
Find the area of trapezium RSDC
(a) 84 cm
(b) 68 cm
(0) 92 cm
to
(d) 78 cm
O
O​

Answer 1

Answer:

b) 68 centimetre

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given In the given diagram, PQ and RS are common tangents to the two circles with centres C and D. Find the area of trapezium RSDC

• PQ and RS are common tangents and are equal. We need to find the length and also the area of trapezium RSDC. So the tangent will be 90 degree. So draw a line parallel to RS. So we will get a right triangle. So we have hypotenuse 13 cm and adjacent will be 5 cm (since for 7 cm line is divided by 5 cm and 2 cm). By Pythagoras theorem we need to find the base.
•               So we get Ac^2 = AB^2 + BC^2
•                                13^2 = 5^2 + m^2
•                                169 = 25 + m^2
•                                   m^2 = 169 – 25
•                                     m^2 = 144
•                                    Or m = 12 cm
•     Since the line is parallel let it be cx
•                        So CX = m = 12 cm, RS = 12 cm
•              Therefore PQ = 12 cm (length)
• So Area of trapezium = ½ x h (sum of parallel sides)
•                                        = ½ x 12 x (7 + 2)
•                                      = 6 x 9
•                                      = 54 sq cm

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https://brainly.in/question/30532505