Question

In the given diagram PQ=RQ and ∠x = ∠y, the prove that BP=AR.

Answer 1

Answer:

Infig.∠x=∠yandPQ=PR

inΔPQR

PQ=QR

∠QRP=∠QPR

Angles opposite to equal sides of triangle are equal

∠ERP=∠SPR→(i)

inΔPERandΔRSP

∠ERP=∠SPR

∠REP=∠PSR

PR=RP

ΔPER≅ΔRSP

AASRule

PE=RS

Answer 2

Answer:

BPQ = ARQ

BP = AR (given)

PQ = RQ ( given )

Q = Q ( common)

so,

BPQ congruent to ARQ ( by cpct)

Therefore. BP = AR

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