In the given diagram shows the centre of the circle and ab is parallel to cd ab equals to 24 cm distance between the courts a b and cd is 17 cm if the radius of the circle is 30 sentimeter find the length of the chord cd
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The length of the chord cd given the radius of the circle is 30 sentimeter is,
Consider the figure while going through the following steps:
Construction:
Draw a line perpendicular to the lines ab and cd passing through the center of circle.
Join oc and oa.
Given,
ab = 24 cm
The distance between ab and cd = mn = 17 cm
The radius of circle = oa = oc = 30 cm
In Δ ocn,
oc² = on² + cn²
∵ ∠ n = 90°
on = mn/2 = 17/2 = 8.5 cm
oc = 30 cm (radius)
30² = 8.5² + cn²
cn² = 30² - 8.5² = 827.75
cn = 28.77 cm
from figure it's clear that,
cd = cn + nd
and cn = nd
⇒ cd = cn + cn
⇒ cd = 2 × cn
⇒ cd = 2 × 28.77
∴ cd = 57.5 cm
Therefore the length of chord cd is 57.5 cm
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