In the given digram find 'x'
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1
By angle sum property
<QPR+<PRQ+<PQR = 180
45+68+(3x+16)=180
OPEN THE BRACKET
45+68+3x+16=180
129+3x=180
3x=180-129
3x=51
x=51/3
x=17
<QPR+<PRQ+<PQR = 180
45+68+(3x+16)=180
OPEN THE BRACKET
45+68+3x+16=180
129+3x=180
3x=180-129
3x=51
x=51/3
x=17
Answered by
6
Hey...!! Here Is Your Ans...
Sum Of All Angle Of Triangle = 180°
Therefore,
45 + 68 + 3x + 16 = 180
129 + 3x = 180
3x = 180 - 129
3x = 51
x = 51\3
x = 17
#RS
HOPE THIS HELPS...☺☺
Sum Of All Angle Of Triangle = 180°
Therefore,
45 + 68 + 3x + 16 = 180
129 + 3x = 180
3x = 180 - 129
3x = 51
x = 51\3
x = 17
#RS
HOPE THIS HELPS...☺☺
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