Question

In the given equation √2x-9+x=6, the
extraneous root is
(1) 5
(2) 9
(3)4.5
(4)3
​

Answer 1

Answer:

the answer is 6

Step-by-step explanation:

√2x-9+x=6

√2x+x=6+9

x(√2+1)=15

x=15/√2+1

x=15*(√2-1)/(√2+1)(√2-1)

x=15√2-15/2-1

x=15(√2-1)/1

√2-1=0.4

x=15*0.4

x=6

Answer 2

Answer:(2) 9

Step-by-step explanation:

He actually wanted to ask ✓a + x = 6, where a= 2x-9

i.e. ✓a=6-x

Squaring

2x-9= 36 +x^2 -12x

We obtain a quadratic equation

Apply Quadrilateral Formula,

You will get 9 and 5 as roots

Then check by substituting for each,

9 will not satisfy

Therefore , 9 is extraneous root