Question

In the given equation find amplitude, time period, Y=2.0 sin 20t​

Answer 1

Explanation:

y=0.3sin20π(t+0.05)

y=0.3sin(20πt+π)

Comparing the given equation with the standard equation y=Asin(ωt+ϕ)

By comparison

ω=20π

⇒phi=π

⇒A=0.3

Thus, amplitude and initial phase is known

Amplitude (A)=0.3m

Initial phase (ϕ)=π

Then, for calculating time period

T=

ω

2π

=

20π

2π

=

10

1

s=0.1s

⇒ Time period (T)=0.1s

Also for initial displacement t=0

⇒y=0.3sin(π)=0

Thus, initial displacement =0.