Question

In the given equation,find the value of unknown constant (s) for which the given value (s) is (are) solution of the equation.
kx square+tx+1=0;x=2, x=0.1​

Answer 1

Answer:

Answer

Given, k

2

x+2x+1=0 ______ (1) where a=k, b=2, c=1

since the equation (1) has distinct roots,

b

2

−4ac>0

⇒2

2

−4k>0

⇒4−4k>0

⇒−4k>−4

⇒4k<4

⇒k<1

∴ whenever k < 1 the given equation (1) will have distinct roots.

solution