In the given fgure, AB is a chord of the outer circle and tangent to the inner circle. If the circkes are concentric
and their radii are 13 cm and 5 cm, then find the length of the chord AB.
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According to question,
Radius of larger circle is 5cm
and length of tangent AC to smaller circle is 8cm.
We know that , tangent is perpendicular to radius through point of tangency,
And M, is the mid point of tangent from figure,
so AM=4cm
Therefore ,
△AMO is the right angle triangle, with OM as radius of smaller circle,
So, from pythagorous theorem,
OA²=OM²+AM²
=> 5²=OM²+4²
=> OM=3
=> Hence radius of smaller circle =3cm
so done!
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