Question

In the given fig. ,AB=AC and angleACD=105 find angle BAC​

Answer 1

Answer:

this is your answer....

Answer 2

To find:- /BAC

Proof :- /ACB + /ACD =180°[ Linear pair axiom]

=>/ACB +/105° =180°

=>/ACB=180°-105°

=>/ACB=75°

AB=AC [Given]

/ABC=/ACB=75° [Angles opposite to the equal sides of a triangle are equal]

/BAC+/ABC+/ACB=180°[Angle sum property of a triangle]

=>/BAC+75°+75°=180°

=>/BAC+150°=180°

=>/BAC=180°-150°

=>/BAC=30°

Therefore, /BAC=30°

HOPE THIS WILL HELP YOU with thanks.