In the given fig., AB and CD are two equal chords equidistant from the centre O of a
circle. OP and OQ are perpendiculars on chords AB and CD respectively. If AP = 4 cm, find the length of CD.
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Answer:
Chords equidistant from center are equal in length
∴AB=CD
∴AB=CD=6 cm
Now OP is ⊥ to AB
∴AP=PB=
2
AB
PB=
2
6
=3 cm.
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