Question

in the given fig AB//DE, angle BAC=35 and angle CDE=53,find angle DCE​

Answer 1

Step-by-step explanation:

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Answer 2

$\large\sf{\angle{BAC}=35°}$ and

$\large\sf{\angle{CDE}=53°}$

$\large\sf{\angle{BAE}=\angle{CED}(alternate\:angles)}$

$\large\sf{\angle{BAE}=35°}$

$\therefore$$\large\sf{\angle{CDE}=35°}$

➡$\large\sf{\angle{CDE}+\angle{CED}+\angle{ECD}=180°}$

➡$\large\sf{53°+35°+\angle{ECD}=180°}$

➡$\large\sf{88°+\angle{ECD}=180°}$

➡$\large\sf{\angle{ECD}=180°-88°}$

➡$\large\sf{\angle{ECD}=92°}$