In the given fig. AB parallel to CD find the value of x, y,z
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24
x=55degree(alternate interior angle)
x+75+y=180(sum of all angles of a triangle)
55+75+y=180
130+y=180
y=180-130
y= 50
mark angle o as angle 1
angle 1=angle y (vertically opposite angle)
angle 1+55+z = 180( sum of all angles of triangle)
50+75+z=180
125+z=180
z=180-125
z= 55 degree
x=55
y=50
z=55
x+75+y=180(sum of all angles of a triangle)
55+75+y=180
130+y=180
y=180-130
y= 50
mark angle o as angle 1
angle 1=angle y (vertically opposite angle)
angle 1+55+z = 180( sum of all angles of triangle)
50+75+z=180
125+z=180
z=180-125
z= 55 degree
x=55
y=50
z=55
Harshitasood:
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Answered by
1
Step-by-step explanation:
x=55°
y=50°
z=55°
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